Does anyone have contact with these two guys (And any of the regular posters that have recently vacated)? The site is working better than I ever remember it working. Southern Hemisphere rugby is up and running again. I reckon its time for a return of the old guard!
It'll also be good to see some of the non-saffas return, Redsman, Cloudy, Bec's etc etc.
BB
Why do you not ask the ED to e-mail to the two members a request to ask them to return to the site. The same applies to oimatey as well,
I actually noted that both oimatey and rooinek are involved in the Foxsport competition and in fact of the Ruckers Forum 1 League started to accommodate site members wishing to participate in the competition.
So they are still around and some encouragement on the part of ED \and other members may help.
Hear hear get the rascal s back!
ED
Please do the board a favour and send e-mails to oimatey, Rooinek, Saffex, C;oudy and Sasuke San asking them to return to the site since we all seem to miss them on site.
Sasuke was banned, and possibly Rooineck aswell.
...maybe they're waiting for someone to say something intelligent
...o oh look Mozart is good at meths
..and still waiting for someone to say something intelligent...
..and still waiting for someone to say something intelligent...
Redneck is pissed off. If you guys haven't figured that out yet then you're really slow on the up take.
I'll be surprised to see him on here again.
Who knows ... maybe a lengthy time out is all he needs. Can't say I blame him.
Saffex is bored with this MB. He'll stick his nose in from time to time.
There are other guys like DumbAss that's also gone missing. In fact we've lost a lot of posters.
Brycy
Don't expect too much from some Board members.
CC
I agree with you - there are too many provocative and often non-rugby issues on site, I know I am guilty too - but I think both Rooinek and Saffex left being pissed off by one or two of our regular posters and this time I was not guilty.
Lets at least try and get back some posters who left - we can do with discussion of real rugby isses and their views was controversial at tines and that is nothing to respond to the way some did.
...yup and we're still waiting for Bean Brain to apologise to Cloudy for harrassing her relentlessly un til she left - very brave man picking on a woman like that...but i did warn her never to trust the Stormer supporters...and i think Mozart would have to take the toaster in the bathtub challenge before Rooinek would come back such was the love..
Moz I want to see your alternative solution to Fermats last theorem ,dont forget to show all your working out too.
Answer on the back of a stamped self addressed envelope to
1 Doesnt Give a bugger ,
Couldntgiveabrassfarthing Lane,
Slightly to the left of Australia.
Cheers!
...its right of australia.
Brycy old mate I wouldnt hold my breath waiting for Beanshitferbrains to ever do the right thing .Far be it for me to speak for others but yeah hammer meet nailhead.
LOL Wardaddy...maybe that's the solution for Saffa's rugby...game plan...pity we don't have Fermat for a coach....it's very simple and we all understand it...Bahahahahahahaha
The equation a 1 / m + b 1 / m = c 1 / m {\displaystyle a^{1/m}+b^{1/m}=c^{1/m}} can be considered the "inverse" Fermat equation. All solutions of this equation were computed by Lenstra in 1992.[141] In the case in which the mth roots are required to be real and positive, all solutions are given by[142]
a = r s m {\displaystyle a=rs^{m}} b = r t m {\displaystyle b=rt^{m}} c = r ( s + t ) m {\displaystyle c=r(s+t)^{m}}for positive integers r, s, t with s and t coprime.
For the Diophantine equation a n / m + b n / m = c n / m {\displaystyle a^{n/m}+b^{n/m}=c^{n/m}} with n not equal to 1, Bennett, Glass, and Székely proved in 2004 for n > 2, that if n and m are coprime, then there are integer solutions if and only if 6 divides m, and a 1 / m {\displaystyle a^{1/m}} , b 1 / m , {\displaystyle b^{1/m},} and c 1 / m {\displaystyle c^{1/m}} are different complex 6th roots of the same real number.[143]
All primitive integer solutions (i.e., those with no prime factor common to all of a, b, and c) to the optic equation a ? 1 + b ? 1 = c ? 1 {\displaystyle a^{-1}+b^{-1}=c^{-1}} can be written as[144]
a = m k + m 2 , {\displaystyle a=mk+m^{2},} b = m k + k 2 , {\displaystyle b=mk+k^{2},} c = m k {\displaystyle c=mk}for positive, coprime integers m, k.
n = –2The case n = –2 also has an infinitude of solutions, and these have a geometric interpretation in terms of right triangles with integer sides and an integer altitude to the hypotenuse.[145][146] All primitive solutions to a ? 2 + b ? 2 = d ? 2 {\displaystyle a^{-2}+b^{-2}=d^{-2}} are given by
a = ( v 2 ? u 2 ) ( v 2 + u 2 ) , {\displaystyle a=(v^{2}-u^{2})(v^{2}+u^{2}),} b = 2 u v ( v 2 + u 2 ) , {\displaystyle b=2uv(v^{2}+u^{2}),} d = 2 u v ( v 2 ? u 2 ) , {\displaystyle d=2uv(v^{2}-u^{2}),}for coprime integers u, v with v > u. The geometric interpretation is that a and b are the integer legs of a right triangle and d is the integer altitude to the hypotenuse. Then the hypotenuse itself is the integer
c = ( v 2 + u 2 ) 2 , {\displaystyle c=(v^{2}+u^{2})^{2},}so (a, b, c) is a Pythagorean triple.
Integer n < –2There are no solutions in integers for a n + b n = c n {\displaystyle a^{n}+b^{n}=c^{n}} for integers n < –2. If there were, the equation could be multiplied through by a | n | b | n | c | n | {\displaystyle a^{|n|}b^{|n|}c^{|n|}} to obtain ( b c ) | n | + ( a c ) | n | = ( a b ) | n | {\displaystyle (bc)^{|n|}+(ac)^{|n|}=(ab)^{|n|}} , which is impossible by Fermat's Last Theorem.I can count to potato!
haha losers
I think CC is right. Rooi is just gatvol. He might be reading here and he even might be back, but I think he lost interest in the constant fighting. DA might get him out of the shadows if he returns.
...JW sometimes for yr own health you just have to throw all th e toxic people out of yr life...which is what Rooinek has effectively done with Mozart and all his multi attack dogs...he's still playing fantasy football and rugby with us though and always a great competitor..
https://www.facebook.com/JungleVT/videos/2229872563821240/
I hold that we are actually on the top and those other bastards are to the bottom[ who decided who gets to be on top eh ? hahaha] so to the left of Australia .
Mercator can stick his projections the hemispherist bastard,I recall my old science teacher used to turn all the globes "upside down "
Pity about Rooie when he was funny he was very funny that oimatey chap seemed a decent chap.
Apropos of nothing how funny is the Specsavers advertising on he refs jumpers ?
...yea there is no right way up its just the early cartographers were from the NH so put Europe at the top of the world... i was at a lecture once and this Maori lady said that ( inverted version) was the Maori world view of Aotearoa anyway..Wellington i.e Te Whanganui a Tara is at the head of the fish....and the jumping off point to the underworld is down the other end at the tail at Te Reinga Wairua i.e Cape Reinga
If we think about the players who left this site one comes to the conclusion that most departures are caused by sick ideas allowing for personal attacks on fellow members and non-rugby BS instead of dealing with rugby issues,
In that regard there are two members who caused more trouble on this site namely Beeno and Mozart. They should in fact apologize and promise they would behave better, which could lead to return of members who left to come back.
